Question

Como proceder?
Me ajudem!!!!

Answer 1

a)

$-\frac{1}{2}+\frac{4}{x+2}=-\frac{2}{3}\\ \\ \frac{4}{x+2}=-\frac{2}{3}+\frac{1}{2}\\ \\ \frac{4}{x+2}=-\frac{1}{6}\\ \\ x+2=-24\\ \\ x=-24-2\\ \\ \boxed{x=-26}$

b)

$-3-\frac{a+1}{a-4}=0\\ \\ \frac{a+1}{a-4}=-3\\ \\ -3(a-4)=a+1\\ \\ -3a+12=a+1\\ \\ -4a=-11\\ \\ a=\frac{11}{4}$

c)

$\frac{3}{2}=1-\frac{4}{x+2}\\ \\ \frac{3}{2}-1=-\frac{4}{x+2}\\ \\ \frac{1}{2}=-\frac{4}{x+2}\\ \\ x+2=-8\\ \\ x=-8-2\\ \\ x=-10$

d)

$\frac{7}{x^2-49}+\frac{2x}{x-7}=\frac{2x}{x+7}\\ \\ 7+2x(x+7)=2x(x-7)\\ \\ 7+2x^2+14x=2x^2-14x\\ \\ 28x=7\\ \\ x=\frac{7}{28}\\ \\ x=\frac{1}{4}$