Question

COMO POSSO RESOLVER ESSA CONTA; 3X² -7.(X²+1) -6 + X² -5.(-1+X²)

Answer 1

$3x^2 - 7(x^2+1)-6+x^2-5(-1+x^2) = 0\\ 3x^2 -7x^2 + 7 -6+x^2+5-5x^2 = 0\\ 3x^2 - 7x^2 + x^2 - 5x^2 + 7 - 6 + 5 = 0\\ -8x^2 +6 = 0 \\-8x^2 = -6 \\ 8x^2 = 6 \\ x^2 = \frac{6}{8} = \frac{3}{4} \\ x = \sqrt{\frac{3}{4}} = \frac{\sqrt{3}}{\sqrt{4}} \\ x = \frac{\sqrt{3}}{\sqrt{4}} * \frac{\sqrt{4}}{\sqrt{4}} = \frac{\sqrt{12} }{\sqrt{16}} \\ x = \frac{\sqrt{12} }{4} = \frac{2\sqrt{3} }{4} = \frac{\sqrt{3} }{2} \\ \\ \\ S = -\frac{\sqrt{3}}{2} , \frac{\sqrt{3}}{2}$