Question

como fazer isso?

 

 

9y²-24y+16=0

Answer 1

delta = (-24)² - 4 x 9 x 16

delta = 0

 

x = -(-24)/9x2 +- 0/ 9x2

 

x= 24/18 = 12/9 = 4/3

Answer 2

$<var>y^2-24y+16=0\\y=\frac{-b^+_-\sqrt{b^2-4ac}}{2a}\\y=\frac{24^+_-\sqrt{24^2-4*1*16}}{2*1}\\y=\frac{24^+_-\sqrt{576-64}}{2}\\y=\frac{24^+_-16\sqrt2}{2}\\\\y'=\frac{24+16\sqrt2}{2}\\y'=12+8\sqrt2\\\\y''=\frac{24-8\sqrt2}{2}\\y''=12-8\sqrt2\\\\S=(12+8\sqrt8; 12-8\sqrt2)</var>$