Question

como fazer a formula de baskara
$3 {x}^{2} + 8x - 3 = 0$
me ajudem please ?????

Answer 1

3x² + 8x - 3 = 0

a = 3
b = 8
c = - 3

Δ = b² - 4 .a . c
Δ = (8)² - 4 . 3 . (-3)
Δ = 64 - 12 . (-3)
Δ = 64 + 36
Δ = 100

$\mathtt{\dfrac{-b+-~\sqrt{\Delta}}{2~.~a}~~=~~\dfrac{-8+-~\sqrt{100}}{2~.~3}~~=~~\dfrac{-8+-~10}{6}} \\ \\ \\ \mathtt{x' = \dfrac{-8+10}{6}~~=~~\dfrac{2}{6}~~(\div2)~~=~~\dfrac{1}{3}} \\ \\ \\ \mathtt{x'' = \dfrac{-8 - 10}{6}~~=~~-\dfrac{18}{6}~~=~~-3}$

Resposta: S{ - 3   e  1/3}