Question

Como faço essas questões

Answer 1

h) $(2^{x})^{2} -6. 2^{x}+5=0$
$2^{x} =y$
$y^{2} -6y+5=0$

Δ=(-6)²-4.1.5
Δ=36-20
Δ=16
y'=6+4/2
y'=5
y''=6-4/2
y''=1
$2^{x}=1$
x''=0
$2^{x}=5$
x'=log5 na base 2

i)$2^{x} .(2^{2})^{x+1}.(2^{3})^{x+2}=(2^{4})^{x+3}$
$2^{x} .2^{2x+2}.2^{3x+6}=2^{4x+12}$
$2^{x+2x+2+3x+6}=2^{4x+12}$
x+2x+2+3x+6=4x+12
6x+8=4x+12
2x=4
x=2