Question

Como faço a questão 7?

Answer 1

5 = 2/3 . log (1000.E/7)

15/2 = log 1000 + log (E/7)

15/2 = log 10 ³ + log (E/7)

15/2 = 3 + log (E/7)

7,5-3 = log (E/7)

4,5 = log (E/7)

⇒

10^(4,5) = E/7

7.10^(4,5) = E

...

3 = 2/3. log (1000.E/7)

9/2 = log 1000 + log (E/7)

9/2 = 3 + log (E/7)

4,5-3 = log (E/7)

1,5 = log (E/7)

⇒

10^(1,5) = E/7

7.10^(1,5) = E

Dividindo:

7.10^(4,5) / 7.10^(1,5) =

10^(4,5) . 10^( -1,5) =

10^[4,5 + (-1,5)] =

10^3 =

1000 a)