Question

Como eu resolvo o logaritmo de base 4 e logaritmando 128?

Answer 1

log(4)128 = x
4^x = 128
128|2
064|2
032|2
016|2
008|2
004|2
002|2
001 --> 128 = 2^7

(2²)^x = 2^7 --> 2x = 7 --> x = 7/2

Answer 2

$\log_4128=x \\ \\ 4^x=128 \\ \\ 2^{2x} =2^7 \\ \\ 2x=7 \\ \\ x= \frac{7}{2}$
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