Question

como eu faco a questao 6 racionalize o denominador de cada fracao

A)2 sobre √7+√5

B) 7 sobre 3-√2

C)5+√11 sobre 3-√11

Answer 1

Resposta:

A)√7-√5

B)3+√2

C) -(15+8√11+11)/2

Explicação passo a passo:

A)( 2/(√7+√5))((√7-√5)/(√7-√5)))==>√7-√5

B)(7/(3-√2))((3+√2)/(3+√2))===> 3+√2

C)((5+√11)/( 3-√11))((3+√11)/(3+√11))===> -(15+8√11+11)/2

Answer 2

Resposta:

$\textsf{Leia abaixo}$

Explicação passo a passo:

$\mathsf{\left(\dfrac{2}{\sqrt{7} + \sqrt{5}}\right)}$

$\mathsf{\left(\dfrac{2}{\sqrt{7} + \sqrt{5}}\right)\:.\:\left(\dfrac{\sqrt{7} - \sqrt{5}}{\sqrt{7} - \sqrt{5}}\right)}$

$\mathsf{\left(\dfrac{2\sqrt{7} - 2\sqrt{5}}{7 - 5}\right)}$

$\mathsf{\left(\dfrac{\not2\sqrt{7} - \not2\sqrt{5}}{\not2}\right)}$

$\boxed{\boxed{\mathsf{\sqrt{7} - \sqrt{5}}}}$

$\mathsf{\left(\dfrac{7}{3 - \sqrt{2}}\right)}$

$\mathsf{\left(\dfrac{7}{3 - \sqrt{2}}\right)\:.\:\left(\dfrac{3 + \sqrt{2}}{3 + \sqrt{2}}\right)}$

$\mathsf{\left(\dfrac{21 + 7\sqrt{2}}{9 - 2}\right)}$

$\mathsf{\left(\dfrac{21 + \not7\sqrt{2}}{\not7}\right)}$

$\boxed{\boxed{\mathsf{3 + \sqrt{2}}}}$

$\mathsf{\left(\dfrac{5 + \sqrt{11}}{3 - \sqrt{11}}\right)}$

$\mathsf{\left(\dfrac{5 + \sqrt{11}}{3 - \sqrt{11}}\right)\:.\:\left(\dfrac{3 + \sqrt{11}}{3 + \sqrt{11}}\right)}$

$\mathsf{\left(\dfrac{26 + 8\sqrt{11}}{9 - 11}\right)}$

$\boxed{\boxed{\mathsf{-13 - 4\sqrt{11}}}}$