Question

como escreve 5x²+4x-50=4x²-29 na forma reduzida ?

Answer 1

$5x^2+4x-50=4x^2-29 \\\\\\ 5x^2+4x-50-4x^2+29=0 \\\\ x^{2} +4x-21=0$

Essa é a forma reduzida, calculando temos:

$\Delta=b^2-4ac\to \Delta=4^2-4*1*(-21)\to \Delta=16+84\to \Delta=100\\\\\\ x' \neq x''\\\\\\ x= \frac{-b \pm \sqrt{\Delta} }{2a} \to x= \frac{-4 \pm \sqrt{100} }{2*1} \to x= \frac{-4 \pm 10 }{2} \to \\\\\\ x'= \frac{-4 + 10 }{2} \to x'= \frac{6 }{2} \to x'=3\\\\\\ x''= \frac{-4 - 10 }{2} \tox''= \frac{-14 }{2} \to x''=-7\\\\\\\\ S=(-7;3)$

Espero ter ajudado...