COMO EFETUAR AS OPERAÇÕES
a) (x+y)(x+2y)
b) (x²+x+3)(-x+3)
c) (8x²-4x+5)÷(x-2)
Soluções para a tarefa
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Boa noite!
Solução!
![a) ~~(x+y)\times(x+2y)\\\\
~~~~~~( x^{2} +2xy+xy+2y^{2})= \boxed{Respostax^{2}+3xy+2y^{2} }\\\\\\\\\
b)~~ ( x^{2} +x+3)(-x+3)~\\\\\
~~~~~~(- x^{3}+3 x^{2}- x^{2} +3x-3x+9)= \boxed{Resposta- x^{3}+2x^{2}- x^{2} +9 }](https://tex.z-dn.net/?f=a%29+%7E%7E%28x%2By%29%5Ctimes%28x%2B2y%29%5C%5C%5C%5C%0A%7E%7E%7E%7E%7E%7E%28+x%5E%7B2%7D+%2B2xy%2Bxy%2B2y%5E%7B2%7D%29%3D+%5Cboxed%7BRespostax%5E%7B2%7D%2B3xy%2B2y%5E%7B2%7D+%7D%5C%5C%5C%5C%5C%5C%5C%5C%5C%0A++%0Ab%29%7E%7E+%28+x%5E%7B2%7D+%2Bx%2B3%29%28-x%2B3%29%7E%5C%5C%5C%5C%5C%0A%7E%7E%7E%7E%7E%7E%28-+x%5E%7B3%7D%2B3+x%5E%7B2%7D-+x%5E%7B2%7D+%2B3x-3x%2B9%29%3D+%5Cboxed%7BResposta-+x%5E%7B3%7D%2B2x%5E%7B2%7D-+x%5E%7B2%7D+%2B9+%7D "a) ~~(x+y)\times(x+2y)\\\\
~~~~~~( x^{2} +2xy+xy+2y^{2})= \boxed{Respostax^{2}+3xy+2y^{2} }\\\\\\\\\
b)~~ ( x^{2} +x+3)(-x+3)~\\\\\
~~~~~~(- x^{3}+3 x^{2}- x^{2} +3x-3x+9)= \boxed{Resposta- x^{3}+2x^{2}- x^{2} +9 }")
No terceiro exercício vamos usar o método da chave.
![c)~~ \dfrac{8 x^{2}-4x+5 }{x-2} \\\\\\\
~~~8 x^{2} -4x+5|\underline{~~x-2~~~~}~\\
\underline{-8 x^{2} +16x}~~~~~8x+12\\
~~~0~~~~~~~12x+5\\
~~~~~~~~~\underline{-12x+24}\\
~~~~~~~~~~~~~0~~+29\\\\\\\\
D(x)=8 x^{2}-4x+5\\\\
d(x)=(x-2)\\\\
q(x)=(8x+12)\\\\
R(x)=29\\\\\
D(x)=d(x)\times q(x)+R(x)](https://tex.z-dn.net/?f=c%29%7E%7E+%5Cdfrac%7B8+x%5E%7B2%7D-4x%2B5+%7D%7Bx-2%7D+%5C%5C%5C%5C%5C%5C%5C%0A%7E%7E%7E8+x%5E%7B2%7D+-4x%2B5%7C%5Cunderline%7B%7E%7Ex-2%7E%7E%7E%7E%7D%7E%5C%5C%0A%5Cunderline%7B-8+x%5E%7B2%7D+%2B16x%7D%7E%7E%7E%7E%7E8x%2B12%5C%5C%0A+%7E%7E%7E0%7E%7E%7E%7E%7E%7E%7E12x%2B5%5C%5C%0A%7E%7E%7E%7E%7E%7E%7E%7E%7E%5Cunderline%7B-12x%2B24%7D%5C%5C%0A%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E%7E0%7E%7E%2B29%5C%5C%5C%5C%5C%5C%5C%5C%0AD%28x%29%3D8+x%5E%7B2%7D-4x%2B5%5C%5C%5C%5C%0Ad%28x%29%3D%28x-2%29%5C%5C%5C%5C%0Aq%28x%29%3D%288x%2B12%29%5C%5C%5C%5C%0AR%28x%29%3D29%5C%5C%5C%5C%5C%0AD%28x%29%3Dd%28x%29%5Ctimes+q%28x%29%2BR%28x%29%0A "c)~~ \dfrac{8 x^{2}-4x+5 }{x-2} \\\\\\\
~~~8 x^{2} -4x+5|\underline{~~x-2~~~~}~\\
\underline{-8 x^{2} +16x}~~~~~8x+12\\
~~~0~~~~~~~12x+5\\
~~~~~~~~~\underline{-12x+24}\\
~~~~~~~~~~~~~0~~+29\\\\\\\\
D(x)=8 x^{2}-4x+5\\\\
d(x)=(x-2)\\\\
q(x)=(8x+12)\\\\
R(x)=29\\\\\
D(x)=d(x)\times q(x)+R(x)")
Boa noite!
Bons estudos!
Solução!
No terceiro exercício vamos usar o método da chave.
Boa noite!
Bons estudos!
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