Question

como determinar o log de 2 na base 32 =x

Answer 1

${2}^{x} = 32 \\ {2}^{x} = {2}^{5 } \\ x = 5$

Answer 2

㏒₃₂2=x

32ˣ=2

log₂2÷log₂32=1÷5=1/5

32 elevado a 1/5 = raiz 5 de 32 = 2

r:1/5