Como determina o 8° termo da P.G com (1/243,1/81,1/27,...)
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Bom dia Gisllany!
Solução!
![q= \dfrac{a2}{a1} \\\\\
q= \dfrac{1}{ \dfrac{81}{ \dfrac{1}{243} } } \\\\\\
q= \dfrac{1}{81}\times \dfrac{243}{1}\\\\\\
q= \dfrac{243}{81}\\\\\
q=3](https://tex.z-dn.net/?f=q%3D+%5Cdfrac%7Ba2%7D%7Ba1%7D+%5C%5C%5C%5C%5C%0Aq%3D+%5Cdfrac%7B1%7D%7B+%5Cdfrac%7B81%7D%7B+%5Cdfrac%7B1%7D%7B243%7D+%7D+%7D+%5C%5C%5C%5C%5C%5C%0Aq%3D+%5Cdfrac%7B1%7D%7B81%7D%5Ctimes+%5Cdfrac%7B243%7D%7B1%7D%5C%5C%5C%5C%5C%5C%0Aq%3D+%5Cdfrac%7B243%7D%7B81%7D%5C%5C%5C%5C%5C%0Aq%3D3+++ "q= \dfrac{a2}{a1} \\\\\
q= \dfrac{1}{ \dfrac{81}{ \dfrac{1}{243} } } \\\\\\
q= \dfrac{1}{81}\times \dfrac{243}{1}\\\\\\
q= \dfrac{243}{81}\\\\\
q=3")
Formula da P.G
![an=a1.q^{n-1} \\\\\
a_{8}= \dfrac{1}{243}.3^{8-1}\\\\\
a_{8}= \dfrac{1}{243}.3^{7}\\\\\
a_{8}= \dfrac{1}{243}.2187\\\\\
a_{8}= \dfrac{2187}{243} \\\\\
a_{8}=9](https://tex.z-dn.net/?f=an%3Da1.q%5E%7Bn-1%7D+%5C%5C%5C%5C%5C%0Aa_%7B8%7D%3D+%5Cdfrac%7B1%7D%7B243%7D.3%5E%7B8-1%7D%5C%5C%5C%5C%5C+%0Aa_%7B8%7D%3D+%5Cdfrac%7B1%7D%7B243%7D.3%5E%7B7%7D%5C%5C%5C%5C%5C+%0Aa_%7B8%7D%3D+%5Cdfrac%7B1%7D%7B243%7D.2187%5C%5C%5C%5C%5C%0Aa_%7B8%7D%3D+%5Cdfrac%7B2187%7D%7B243%7D+%5C%5C%5C%5C%5C%0Aa_%7B8%7D%3D9 "an=a1.q^{n-1} \\\\\
a_{8}= \dfrac{1}{243}.3^{8-1}\\\\\
a_{8}= \dfrac{1}{243}.3^{7}\\\\\
a_{8}= \dfrac{1}{243}.2187\\\\\
a_{8}= \dfrac{2187}{243} \\\\\
a_{8}=9")
Bom dia!
Bons estudos!
Solução!
Formula da P.G
Bom dia!
Bons estudos!
Gisllany:
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Dê nada!
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