Question

Como calculo lim x→2 (√2x²+3x+2)/6-4x

Answer 1

Olá!


$\\ \displaystyle \mathsf{\lim_{x \to 2} \frac{\sqrt{2x^2 + 3x + 2}}{6 - 4x} =} \\\\\\ \mathsf{\frac{\sqrt{2 \cdot (2)^2 + 3 \cdot (2) + 2}}{6 - 4 \cdot (2)} =} \\\\\\ \mathsf{\frac{\sqrt{2 \cdot 4 + 6 + 2}}{6 - 8} =} \\\\\\ \mathsf{\frac{\sqrt{16}}{- 2} =} \\\\\\ \mathsf{\frac{4}{- 2} =} \\\\\\ \boxed{\mathsf{- 2}}$