como calcular o cosseno de 25π/3?
Soluções para a tarefa
Respondido por
19
tg(25π/3) = tg(24π/3 + π/3)
tg(25π/3) = tg(8π + π/3)
tg(25π/3) = sen(8π + π/3)/cos(8π + π/3)
sen(8π + π/3) = sen(8π)cos(π/3) + cos(8π)sen(π/3)
sen(8π + π/3) = 0.1/2 + 1.√3/2
sen(8π + π/3) = √3/2
cos(8π + π/3) = cos(8π)cos(π/3) - sen(8π)sen(π/3)
cos(8π + π/3) = 1.1/2 - 0.√3/2
cos(8π + π/3) = 1/2
tg(25π/3) = sen(25π/3)/cos(25π/3)
tg(25π/3) = (√3/2)/(1/2)
tg(25π/3) = √3
tg(25π/3) = tg(8π + π/3)
tg(25π/3) = sen(8π + π/3)/cos(8π + π/3)
sen(8π + π/3) = sen(8π)cos(π/3) + cos(8π)sen(π/3)
sen(8π + π/3) = 0.1/2 + 1.√3/2
sen(8π + π/3) = √3/2
cos(8π + π/3) = cos(8π)cos(π/3) - sen(8π)sen(π/3)
cos(8π + π/3) = 1.1/2 - 0.√3/2
cos(8π + π/3) = 1/2
tg(25π/3) = sen(25π/3)/cos(25π/3)
tg(25π/3) = (√3/2)/(1/2)
tg(25π/3) = √3
Perguntas interessantes
Matemática,
9 meses atrás
Ed. Técnica,
9 meses atrás
Português,
9 meses atrás
Matemática,
1 ano atrás
História,
1 ano atrás
Geografia,
1 ano atrás
Matemática,
1 ano atrás