Question

Como calcular 6x ao quadrado + x-1=0

Answer 1

Resposta:

Explicação passo-a-passo:

$Aplicando~a~f\'{o}rmula~de~Bhaskara~para~6x^{2}+1x-1=0~~\\e~comparando~com~(a)x^{2}+(b)x+(c)=0,~temos~a=6{;}~b=1~e~c=-1\\\\\Delta=(b)^{2}-4(a)(c)=(1)^{2}-4(6)(-1)=1-(-24)=25\\\\x^{'}=\frac{-(b)-\sqrt{\Delta}}{2(a)}=\frac{-(1)-\sqrt{25}}{2(6)}=\frac{-1-5}{12}=\frac{-6}{12}=-\frac{1}{2} \\\\x^{''}=\frac{-(b)+\sqrt{\Delta}}{2(a)}=\frac{-(1)+\sqrt{25}}{2(6)}=\frac{-1+5}{12}=\frac{4}{12}=\frac{1}{3}\\\\S=\{-\frac{1}{2} ,~\frac{1}{3}\}$