Question

como calcular 6 elevado a 3/8 elevado a 4 e 9 elevado a 4/7 elevado a 3

Answer 1

$(6^{ \frac{3}{8} })^4 = 6^{ \frac{12}{8} } = 6^{ \frac{6}{4} } = 6^{ \frac{3}{2} } = \sqrt{6^3} = \sqrt{6^2 . 6} = 6 \sqrt{6}$

$(9^{ \frac{4}{7} })^3 = 9^{ \frac{12}{7} } = \sqrt[7]{9^{12}} = \sqrt[7]{9^7 . 9^5} = 9 \sqrt[7]{9^5} = 9 \sqrt[7]{(3^2)^5} = 9 \sqrt[7]{3^{10}} = 9 \sqrt[7]{3^7 . 3^3} \\ 9.3 \sqrt[7]{3^3} = 27 \sqrt[7]{27}$ ou $27 \sqrt[7]{3^3} = 27 . 3^{ \frac{3}{7} }$