Question

Como calcular (4-a)/(4+a^2) = 0?

Answer 1

$\frac{4- \alpha }{4+ \alpha ^{2} } =0 ==> \frac{4 - \alpha }{4- \alpha ^{2} }+ \frac{1}{1} = \frac{1}{1} ==> \frac{4-a+4+a^2}{4+a^2}=1 4- \alpha + 4+ \alpha ^{2} =4+ \alpha ^{2} 4- \alpha =0 -\alpha =-4 \alpha =4$