Question

combinação de a) 4!+5!/3+2!=
b) 10!/12!

Answer 1

a)
$4!+\frac{5!}{3!}+2!=24+\frac{120}{3.2}+2=24+20+2=46$

b)
$\frac{10!}{12!}=\frac{10!}{12.11.10!}=\frac{1}{12.11}=\frac{1}{132}$