Question

Com logx a = 5 , logx b= 2 e logx c = − 1 , calcule: a) logx ( a.b/ c ) b) logx a2b2/ √c2

Answer 1

logx(a.b/c)=
logxa+logxb-logxc=
5+2-(-1)=
7+1=
8

logx a^2.b^2/Vc^2=
logx a^2.b^2/c=
logx a^2 + logx b^2 - logx c=
2logx a+ 2logx b- logx c= 
2.5+2.2-(-1)=
10+4+1=
14+1=
15