Física, perguntado por oelekekekekw2828, 6 meses atrás

Com a resolução por favor

Anexos:

Soluções para a tarefa

Respondido por PERE1RABR
2

\Huge \text {$ \sf   5)  \dfrac {} {}$}\\\Huge \text {$ \sf  F = m.a     \dfrac {} {}$}\\\Huge \text {$ \sf   225 = 15.a   \dfrac {} {}$}\\\Huge \text {$ \sf    225 = 15a  \dfrac {} {}$}\\\Huge \text {$ \sf    a =   \dfrac {225} {15}$}\\\Huge \text {$ \sf    a = 15 m/s^{2}   \dfrac {} {}$}

_________________________________________________________

\Huge \text {$ \sf   6)   \dfrac {} {}$}\\\Huge \text {$ \sf   F_{1} - F_{2}  =  \dfrac {} {}$}\\\Huge \text {$ \sf  25 -  15   \dfrac {} {}$}\\\Huge \text {$ \sf   10 N   \dfrac {} {}$}\\\\\\\\\\\\\\\\\Huge \text {$ \sf   F = m.a   \dfrac {} {}$}\\\Huge \text {$ \sf   10 = 5.a   \dfrac {} {}$}\\\Huge \text {$ \sf   10 = 5a   \dfrac {} {}$}\\\Huge \text {$ \sf   a =    \dfrac {10} {5}$}\\\Huge \text {$ \sf   a = 2 m/s^{2}    \dfrac {} {}$}

_________________________________________________________

\Huge \text {$ \sf    7)  \dfrac {} {}$}\\\Huge \text {$ \sf   m_{1} + m_{2} =     \dfrac {} {}$}\\\Huge \text {$ \sf  15 + 35    \dfrac {} {}$}\\\Huge \text {$ \sf  50 kg    \dfrac {} {}$}\\\\\\\\\\\\\\\Huge \text {$ \sf   F = m.a   \dfrac {} {}$}\\\Huge \text {$ \sf   350 = 50.a   \dfrac {} {}$}\\\Huge \text {$ \sf   350 = 50a   \dfrac {} {}$}\\\Huge \text {$ \sf    a =  \dfrac {350} {50}$}\\\Huge \text {$ \sf  a = 7 m/s^{2}     \dfrac {} {}$}

Perguntas interessantes