Question

Com a Fórmula de Bhaskara resolva: x^2+2x-8=0

Answer 1

x^2+2x-8+=0
delta:b^2-4.a.c
delta: (2)^2-4.1.(-8)
delta:4+32=36
-b+-vdelta/2.a
-2+-v36/2.1
2+-6/2
x' 2+6/2=8/2=4
x" 2-6/2=-4/2=-2