Question

com a fórmula de Bhaskara resolva a questão:
x² + 8x + 16 = 0

Answer 1

a= 1
b= 8
c= 16

8 ao quadrado . -4 . 1 . 16
 64-64
    0

-8 -+ raiz de 0  / 2 .1

-8 +- 0 / 2 = 4

Answer 2

X²+8X+16=0

a=1 b=8 c=16

$x= \frac{ -b_{-}^+\sqrt{b^2- 4.a.c}}{2.a}$

$x= \frac{ -8_{-}^+\sqrt{8^2- 4.1.16}}{2.1}$

$x= \frac{ -8_{-}^+\sqrt{64- 64}}{2}$

$x= \frac{ -8_{-}^+\sqrt{0}}{2}$

$x= \frac{ -8_{-}^+{0}}{2}$

$x^I= \frac{ -8+{0}}{2}= \frac{-8}{2}= -4$

$x^I^I= \frac{ -8-{0}}{2}= \frac{-8}{2} =-4$