Question

Coloque o "t" do outro lado da igualdade nesta formula: Vc = Vmax * (1-e^-(t/RC))
E nesta Vc = Vmax * (e^-(t/RC))

Answer 1

$V_c=V_{max} * (1-e^{-\frac{t}{RC}})$

$\frac{V_c}{V_{max}}= 1-e^{-\frac{t}{RC}}$

$\frac{V_c}{V_{max}} - 1= -e^{-\frac{t}{RC}}$

$-\frac{V_c}{V_{max}} + 1= e^{-\frac{t}{RC}}$

$ln(-\frac{V_c}{V_{max}}+1)= ln(e^{-\frac{t}{RC}})$

$ln(-\frac{V_c}{V_{max}}+1)=-\frac{t}{RC}*ln(e)$

$ln(-\frac{V_c}{V_{max}}+1)=-\frac{t}{RC}$

$t = -RC *ln(-\frac{V_c}{V_{max}<span>}+1)</span>$

Answer 2

Vc = Vmax.[1 - e^(-t/RC)]
Vc/Vmax = [1 - e^(-t/RC)]
1 - Vc/Vmax = e^(-t/RC)
e^(-t/RC)= 1 - Vc/Vmax
-t/RC = ln(1 - Vc/Vmax)
t = - RC.ln(1 - Vc/Vmax)


Vc = Vmax . (e^-(t/RC))
Vc/Vmax=e^-(t/RC)
e^-(t/RC)=Vc/Vmax
-t/RC = ln(Vc/Vmax)
t = - RC.ln(Vc/Vmax)