Question

Coloque na forma a x²+bx-c=0 os seguintes:

(x-5)²-9=0
(x+1)²-x=7
(x+4)²=3(x+2)
(x-2).(x+1)=3

Answer 1

${(x - 5)}^{2} - 9 = 0 \\ {x }^{2} - 10x + 25 - 9 = 0 \\ {x}^{2} - 10x + 16 = 0 \\ a = 1 \: \: \: b = 10 \: \: \: c = 16$

${(x + 1)}^{2} - x = 7 \\ {x}^{2} + 2x + 1 - x = 7 \\ {x}^{2} + x + 1 - 7 = 0 \\ {x}^{2} + x - 6 = 0 \\ a = 1 \: \: \: b = 1 \: \: \: c = - 6$

${(x + 4)}^{2} = 3( x + 2) \\ {x }^{2} + 8x + 16 = 3x + 6 \\ { x}^{2} + 8x - 3x + 16 - 6 = 0 \\ {x}^{2} + 5x + 10 = 0 \\ a = 1 \: \: \: b = 5 \: \: \: c = 10$

$( x - 2)(x + 1) = 3 \\ {x}^{2} + x - 2x - 2 = 3 \\ {x}^{2} - x - 2 - 3 = 0 \\ {x}^{2} - x - 5 = 0 \\ a = 1 \: \: \: b = - 1 \: \: \: c = - 5$