Question

coeficiente angular e a funcao linear de (-2,1) e (5,-2)

Answer 1

$m = \frac{yb - ya}{xb - xa}$
m=-2-1/5-(-2)= 1/3 coeficiente angular

$y = mx + n$
-2=1/3×5
-2=5/3
-2-5/3
n= 3/3=1
coeficiente linear 1

me corrigem se estiver errado

Answer 2

Sejam os Pontos A(-2, 1) e B(5, -2)
Coeficiente angular da reta: $m= \frac{y_A-y_B}{x_A-x_B}$

$m= \frac{y_A-y_B}{x_A-x_B} = \frac{-2-1}{5-(-2)} = \frac{-3}{7} = -\frac{3}{7} \\ \\m =- \frac{3}{7}$

Equação da reta
$(y-y_A)= m \cdot(x-x_A)\\ \\(y-1)=- \frac{3}{7} \cdot[x-(-2)]\\ \\y-1= -\frac{3}{7} \cdot[x+2]\\ \\7y-7= - 3\cdot[x+2]\\ \\7y-7= -3x-6\\ \\7y= -3x-6+7\\ \\7y= -3x+1\\ \\y= -\frac{3x}{7} + \frac{1}{7}$