Question

circulo de diametro igual 32cm (area e comprimento)

Answer 1

$\Large\boxed{\begin{array}{l}\underline{\rm Comprimento\,do\,c\acute irculo}\\\sf C=D\cdot\pi\\\sf D\longrightarrow di\hat ametro\\\underline{\rm \acute Area\,do\,c\acute irculo}\\\sf A=\pi\cdot r^2\\\sf D=32\,cm\\\sf r=\dfrac{D}{2}\\\\\sf r=\dfrac{32}{2}\\\\\sf r=16\,cm\\\underline{\boldsymbol{C\acute alculo\,do\,comprimento\!:}}\\\sf C=D\cdot \pi\\\sf C=32\cdot3,14\\\sf C=100,48\,cm\\\underline{\boldsymbol{ \acute Area\,do\,c\acute irculo:}}\\\sf A=\pi\cdot r^2\\\sf A=3,14\cdot16^2\\\sf A=3,14\cdot256\\\sf A=803,84\,cm^2\end{array}}$

Answer 2

Resposta:

$\textsf{Segue a resposta abaixo}$

Explicação passo-a-passo:

$\mathsf{d=32\,cm;~\pi=3{,}14;~A=\,?;~C=\,? }$

$\mathsf{A=\pi\cdot\left(\dfrac{ d}{2}\right)^2}$

$\mathsf{ A=3{,}14\cdot\left(\dfrac{32}{2}\right)^2}$

$\mathsf{A=3{,}14\cdot16^2 }$

$\mathsf{A=3{,}14\cdot256 }$

$\boxed{\boxed{\mathsf{A=803{,}84\,cm^2}}}$

$\mathsf{C=\pi\cdot d }$

$\mathsf{ C=3{,}14\cdot32}$

$\boxed{\boxed{ \mathsf{ C=100{,}48\,cm}}}$