Question

(cesgranrio) se log x=3 e log y = - 2, então qual o valor de: (img)

Answer 1

Olá, Yunnac.

$\log\sqrt[3]{x^2y}=\log(x^2y)^{\frac13}=\frac13\log(x^2y)=\frac13(\log x^2+\log y)=\\\\=\frac13(2\log x+\log y)=\frac13(2\cdot3-2)=\frac13(6-2)=\boxed{\frac43}$