Question

caulcule o valor de x e y​

Answer 1

Explicação passo-a-passo:

• $\sf sen~60^{\circ}=\dfrac{x}{12\sqrt{3}}$

$\sf \dfrac{\sqrt{3}}{2}=\dfrac{x}{12\sqrt{3}}$

$\sf 2x=\sqrt{3}\cdot12\sqrt{3}$

$\sf 2x=12\cdot3$

$\sf 2x=36$

$\sf x=\dfrac{36}{2}$

$\sf x=18$

• $\sf cos~60^{\circ}=\dfrac{y}{12\sqrt{3}}$

$\sf \dfrac{1}{2}=\dfrac{y}{12\sqrt{3}}$

$\sf 2y=12\sqrt{3}$

$\sf y=\dfrac{12\sqrt{3}}{2}$

$\sf y=6\sqrt{3}$