Question

caulcule as raizes das equações do 2°grau

Answer 1

x² -2x - 3 = 0
-b/c = 2/-3 = 3 -1/3. -1 => x'=3, x"=-1

x² +20x -525 = 0
-b/c= -20/-525= 15 -35/15. -35 => S:{15,-35}