Question

caucule os logaritmos :
a)log 3/2;16/81


b)log 10.000


c)log 256 ;128

Me ajudemmm !! e pra amanha

Answer 1

Logₐᵇ = x  →  aˣ = b

a)

$(\frac{3}{2})^{x} = (\frac{81}{16})^{-1} \\ \\ (\frac{3}{2})^{x} = (\frac{3}{2})^{-4} \\ x =-4$

b)

$10^{x} = 10^{4} \\ x = 4$

c)

$2^{8x} = 2^{7}\\ 8x = 7\\ x =\frac{7}{8}$