Question

Caucule a soma: $\frac{-x^2+4x-1}{x^2-1} + \frac{x-2}{x+1}$

Answer 1

Olá!

$\frac{-x^2+4x-1}{x^2-1} + \frac{x-2}{x+1} \\ \\ \frac{-x^2+4x-1}{(x + 1) \times (x - 1)} + \frac{x-2}{(x+1)} = \\ \\ \frac{-x^2+4x-1}{(x^2-1)} + \frac{x-2}{( {x}^{2} - 1)} = \\ \\ \frac{(-x^2+4x-1) \times 1}{(x^2-1)} + \frac{(x-2) \times (x - 1)}{ {(x}^{2} -1)} \\ \\ = - {x }^{2} + 4x - 1 + {x}^{2} - 3x + 2 \\ \\ = - {x}^{2} + {x}^{2} + 4x - 3x + 2 \\ \\ = 4x - 3x + 2 \\ \\= x + 2$

Espero ter ajudado!

bom dia !