Question

caucular a cotg 330 graus

Answer 1

Cotg = inverso da tangente = cosX/senX

 

 

Cotg = Cos 330° / sen 330°

 

Cotg = raiz de 3 / 2  / -1/2

 

Cotg = 2raiz de 3 / -2

 

Cotg330° =  - raiz de 3

Answer 2

$<var>cotgx = \frac{cosx}{senx}</var>$

 

$<var>cotg330= \frac{cos330}{sen330}</var>$

 

330° = 30°

 

$<var>cotg330 = \frac{cos30}{sen30}</var>$

 

sen30° = $<var>\frac{1}{2}</var>$

de 330° será negativo

 

cos30° = $<var>\frac{\sqrt{3}}{2}</var>$

 

$<var>cotg330 = \frac{\frac{\sqrt{3}}{2}}{-\frac{1}{2}}</var>$

 

Multiplicando as extremidades.

$<var>cotg330 = \frac{2\sqrt{3}}{-2}</var>$

 

$<var>\boxed{cotg330 = -\sqrt{3}}</var>$