Question

cálculo de f (x)-3 x+12×-9.sabendo f (x)=0.​

Answer 1

Resposta:

f( \frac{1}{2})= \frac{ \frac{1}{2} }{2} - \frac{2}{3}f(

2

1

)=

2

2

1

−

3

2

f( \frac{1}{2})= \frac{1}{4} - \frac{2}{3}f(

2

1

)=

4

1

−

3

2

f( \frac{1}{2})= \frac{3-8}{12}= \frac{-5}{12}f(

2

1

)=

12

3−8

=

12

−5

f( \frac{1}{2})= \frac{-5}{12}f(

2

1

)=

12

−5

f( \frac{-2}{3})= \frac{ \frac{-2}{3} }{2} - \frac{2}{3}f(

3

−2

)=

2

3

−2

−

3

2

f( \frac{-2}{3})= \frac{-1}{3} - \frac{2}{3}= \frac{-1-2}{3} < br / > < br / > [texf( \frac{-2}{3}) = \frac{-3}{3}=-1f(

3

−2

)=

3

−1

−

3

2

=

3

−1−2

<br/><br/> [texf(

3

−2

)=

3

−3

=−1

f(1/2) + f(-2/3)

-5/12 + (-1)

-5/12 - 1

(-5-12)/12

-17/12

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