Question

cálculo da equação por favor!​

Answer 1

25^x-23.5^x=50

(5^x)²-23.5^x=50

5^x=y

y²-23y=50

y²-23y-50=0

y=-(-23)+-\/(-23)²-4.1.-50/2

y=23+-\/529+200/2

y=23+-\/629/2

y=23+\/629/2

ou

y=23+-\/629/2

5^x=23+\/629/2

log5^x=log(23+\/629/2)

x=5^log(23+\/629/2)