Question

Cálculo da distancia entre os pontos P(3,-3) e Q(-3,3)

Answer 1

$\textbf{Pontos:}\ \boxed{\mathrm{P(x_P;y_P)=P(3;-3)}}\ \mathrm{e}\ \boxed{\mathrm{Q(x_Q;y_Q)=Q(-3;3)}}\\\\ \mathrm{d_{PQ}=\sqrt{\mathrm{(x_Q-x_P)^2+(y_Q-y_P)^2}}=\sqrt{(-3-3)^2+(3-(-3))^2}=}\\\\ \mathrm{=\sqrt{(-6)^2+6^2}=\sqrt{2.6^2}=6\sqrt{2}}\ \to\ \boxed{\mathbf{d_{PQ}=6\sqrt{2}\ u.c.}}$