Question

calculo 1 A alternativa que corresponde à solução de:

Answer 1

$\int x\sqrt{3+2x^2}\ dx\\\\\\u=3+2x^2\\\\\dfrac{du}{dx}=4x\\\\dx=\dfrac{du}{4x}\\\\\\\int x\sqrt u\ \dfrac{du}{4x}\\\\\int\dfrac{\sqrt{u}}{4}\ du\\\\\dfrac14\int u^\frac12\ du\\\\\dfrac14\dfrac{u^{1+\frac12}}{1+\frac12}+C\\\\\dfrac14\dfrac{u^\frac32}{\frac32}+C\\\\\dfrac{u^\frac32}{6}+C\\\\\dfrac{(3+2x^2)^\frac32}{6}+C$

Answer 2

Resposta:

1 (3x-1)4/12+c

2 in(1+2x4)/8+c

3 r(3+2x2)3/6+c

4 -2x cos x+2 senx +c

5 5e3x/3 (x-1/3)+c

6 x2 in x-x2/2+c

7 pi - 2

8 2/3

9 x= r3 tg u

10 x= tg u

Explicação passo-a-passo: