Question

calculee
(x+4)²
(y+3)²
(2x+1)²
(3x+y)²

Answer 1

poduto notavel
$x^{2} + 2*x*4 + 4^{2} = x^{2} + 8x + 16$
$y^{2} + 2*y*3 + 3^{2} = y^{2} + 6y + 9$
$2x^{2} + 2*2x*1 + 1^{2} = 4x^{2} + 4x + 1$
$3x^{2} + 2*3x*y + y^{2} = 9x^{2} + 6xy + y^{2}$

Answer 2

Produto Notável ---> O quadrado do 1° mais duas vezes o 1° multiplicado pelo 2° mais o quadrado do 2°.

$a)~~(x+4)^2\to~~(x+4)(x+4)\to~~ x^2+4x+4x+16\to\\\\ \large\boxed{x^2+8x+16}\\\\\\\\ b)~~(y+3)^2\to~~ (y+3)(y+3)\to~~ y^2+3y+3y+9\to\\\\ \large\boxed{y^2+6y+9}\\\\\\\\ c)~~(2x+1)^2\to~~(2x+1)(2x+1)\to~~ 4x^2+2x+2x+1\to\\\\ \large\boxed{4x^2+4x+1}\\\\\\\\ d)~~(3x+y)^2\to~~ (3x+y)(3x+y)\to~~ 9x^2+3xy+3xy+y^2\to\\\\ \large\boxed{9x^2+6xy+y^2}$