Question

Calcule
( x²+3x-4).(x-2)
(c³+4c²+c).(c-1

Answer 1

( x²+3x-4).(x-2) Aplicar a distributiva
x³ + 3x² -4x -2x² -6x + 8      fazendo as contas com as partes literais iguais 
x³ + x² - 10x + 8



(c³+4c²+c).(c-1) 
c elevado a 4 + 4c³ + c² - c³ -4c² -c     fazendo as contas com as partes literais iguais 
c elevado a 4 +3c³ -2c² -c

Answer 2

a)(x^2+3x-4)(x-2)
x^3+3x^2-4x-2x^2-6x+8
x^3+x^2-10x+8

x^2+3x-4
x-2
_______
-2x^2-6x+8
x^3+3x^2-4x
_____________
x^3+x^2-10x+8

b)(c^3+4c^2+c)(c-1)
c^4+4c^3+c^2-c^3-4c^2-c
c^4+3c^3-3c^2-c

c^3+4c^2+c
c-1
__________
-c^3-4c^2-c
c^4+4c^3+c^2
______________
c^4+3c^3-3c^2-c