Question

calcule:
(x²+2).(x²+6)

Answer 1

(x²+2)(x²+6)
x⁴+6x²+2x²+12
x⁴+8x²+12=0
(x²)²+8(x²)+12=0
seja x²=t
t²+8t+12=0
(t+2)(t+6)
t+2=0^t+6=0
t=-2^t=-6
Obrigado bom simplesmente