Question

CALCULE X,Y,Z e W
teorema de pitagoras

Answer 1

Resposta:

x² = 1²+1²

x = $\sqrt{1^{2}+1^{2}}$

x = 1 + 1

x = 2

--------------------------

y² = 2² + 1²

y = $\sqrt[2]{2^{2}+1^{2}}$

y = 2 + 1

y = 3

---------------------------

z² = 3³ + 1²

z = $\sqrt[2]{3^{2}+1^{2}}$

z = 3 + 1

z = 4

----------------------------

w² = 4² + 1²

w = $\sqrt[2]{4^{2}+1^{2}}$

w = 4 + 1

w = 5

*Espero ter ajudado!

*Bons estudos!!