Question

calcule x, y, z e t
ME AJUDEM POR FAVOR!

Answer 1

$y^2 + 9^2 = 15^2\\y=\sqrt{144}\\ y=12$     $t.z= x^2\\z^2 +x^2=9^2 => z=\sqrt{81-x^2}\\t^2+x^2 = 12^2=> t =\sqrt{144-x^2}\\\\\\logo\\x^2= \sqrt{81-x^2} .\sqrt{144-x^2} \\x^4=(81-x^2). (144-x^2)\\x^4=x^4 -225x^2 +81.144\\225x^2= 9^2.12^2\\x=\sqrt{51,84} \\x=7,2\\\\Assim: z=\sqrt{29,16}   => z=5,4\\t=9,6$