Question

Calcule x sabendo que os ângulos são complementares x/2 +20º 2x-36º

Answer 1

(X/2 + 20¤) + (2X - 36¤) = 90¤

(X + 40¤) + (2X - 36¤) = 90¤

X + 40¤ + X + 36¤ = 90¤

2X + 76¤ = 90¤

2X = 90¤ - 76¤

2X = 54¤

X = 54¤/2

X = 27¤

Answer 2

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$\sf{\dfrac{x}{2}+20^{\circ}+2x-36^{\circ}=90^{\circ}\cdot2}\\\sf{x+40^{\circ}+4x-72^{\circ}=180^{\circ}}\\\sf{5x=180^{\circ}+32^{\circ}}\\\sf{5x=212^{\circ}}\\\sf{x=\dfrac{212^{\circ}}{5}}\\\huge\boxed{\boxed{\boxed{\boxed{\sf{x=42^{\circ}24'}}}}}$