Question

calcule X sabendo que: 2^ log2(x+1) = 3

Answer 1

2^u = 3
u log2 = log 3
u= log 2/ log 3.
log 2 (x+1) = log2/ log3
x+1 = 1/log 3
x= (1/log3) -1 .

Answer 2

2^ log2(x+1) = 3

passa para log na base 2

log2 (3) = log2 (X+1)

corta log2

x+1 = 3

x = 3-1

x=2