Question

calcule: (x/3+y-z²)+(x/2+4y-3z²)

Answer 1

Resposta:

$( \frac{x}{3} + y - {z}^{2} ) + ( \frac{x}{2} + 4y - {3z}^{2} ) = \frac{x}{3} + \frac{x}{2} + y + 4y - {z}^{2} - {3z}^{2} = \frac{2x + 3x}{6} + 5y - 4 {z}^{2} = \frac{5x}{6} + 5y - 4 {z}^{2}$