Calcule valor de A e B, sabendo que A/B = 2/3 sabendo que A²+B²=325
Soluções para a tarefa
Respondido por
4
Olá!
Da condição I:
![\\ \mathsf{\frac{A}{B} = \frac{2}{3}} \\\\ \mathsf{\frac{A}{B} = \frac{2k}{3k}} \\ \mathsf{\frac{A}{B} = \frac{2}{3}} \\\\ \mathsf{\frac{A}{B} = \frac{2k}{3k}}](https://tex.z-dn.net/?f=%5C%5C+%5Cmathsf%7B%5Cfrac%7BA%7D%7BB%7D+%3D+%5Cfrac%7B2%7D%7B3%7D%7D+%5C%5C%5C%5C+%5Cmathsf%7B%5Cfrac%7BA%7D%7BB%7D+%3D+%5Cfrac%7B2k%7D%7B3k%7D%7D)
Isto posto, temos que:
e ![\boxed{\mathsf{B = 3k}} \boxed{\mathsf{B = 3k}}](https://tex.z-dn.net/?f=%5Cboxed%7B%5Cmathsf%7BB+%3D+3k%7D%7D)
Da condição II:
![\\ \mathsf{A^2+B^2=325} \\ \mathsf{(2k)^2 + (3k)^2 = 325} \\ \mathsf{4k^2 + 9k^2 = 325} \\ \mathsf{13k^2 = 325} \\ \mathsf{k^2 = 25} \\ \boxed{\mathsf{k = \pm 5}} \\ \mathsf{A^2+B^2=325} \\ \mathsf{(2k)^2 + (3k)^2 = 325} \\ \mathsf{4k^2 + 9k^2 = 325} \\ \mathsf{13k^2 = 325} \\ \mathsf{k^2 = 25} \\ \boxed{\mathsf{k = \pm 5}}](https://tex.z-dn.net/?f=%5C%5C+%5Cmathsf%7BA%5E2%2BB%5E2%3D325%7D+%5C%5C+%5Cmathsf%7B%282k%29%5E2+%2B+%283k%29%5E2+%3D+325%7D+%5C%5C+%5Cmathsf%7B4k%5E2+%2B+9k%5E2+%3D+325%7D+%5C%5C+%5Cmathsf%7B13k%5E2+%3D+325%7D+%5C%5C+%5Cmathsf%7Bk%5E2+%3D+25%7D+%5C%5C+%5Cboxed%7B%5Cmathsf%7Bk+%3D+%5Cpm+5%7D%7D)
Quando k = - 5, teremos:
![\\ \mathsf{A = 2k} \\ \boxed{\boxed{\mathsf{A = - 10}}} \\ \mathsf{A = 2k} \\ \boxed{\boxed{\mathsf{A = - 10}}}](https://tex.z-dn.net/?f=%5C%5C+%5Cmathsf%7BA+%3D+2k%7D+%5C%5C+%5Cboxed%7B%5Cboxed%7B%5Cmathsf%7BA+%3D+-+10%7D%7D%7D)
E,
![\\ \mathsf{B = 3k} \\ \boxed{\boxed{\mathsf{B = - 15}}} \\ \mathsf{B = 3k} \\ \boxed{\boxed{\mathsf{B = - 15}}}](https://tex.z-dn.net/?f=%5C%5C+%5Cmathsf%7BB+%3D+3k%7D+%5C%5C+%5Cboxed%7B%5Cboxed%7B%5Cmathsf%7BB+%3D+-+15%7D%7D%7D)
Quando k = 5, teremos:
![\\ \mathsf{A = 2k} \\ \boxed{\boxed{\mathsf{A=10}}} \\ \mathsf{A = 2k} \\ \boxed{\boxed{\mathsf{A=10}}}](https://tex.z-dn.net/?f=%5C%5C+%5Cmathsf%7BA+%3D+2k%7D+%5C%5C+%5Cboxed%7B%5Cboxed%7B%5Cmathsf%7BA%3D10%7D%7D%7D)
E,
![\\ \mathsf{B = 3k} \\ \boxed{\boxed{\mathsf{B=15}}} \\ \mathsf{B = 3k} \\ \boxed{\boxed{\mathsf{B=15}}}](https://tex.z-dn.net/?f=%5C%5C+%5Cmathsf%7BB+%3D+3k%7D+%5C%5C+%5Cboxed%7B%5Cboxed%7B%5Cmathsf%7BB%3D15%7D%7D%7D)
Da condição I:
Isto posto, temos que:
Da condição II:
Quando k = - 5, teremos:
E,
Quando k = 5, teremos:
E,
Perguntas interessantes
Matemática,
11 meses atrás
Matemática,
11 meses atrás
Matemática,
11 meses atrás
Geografia,
1 ano atrás
Física,
1 ano atrás
Matemática,
1 ano atrás
Matemática,
1 ano atrás