Question

calcule usando báskhara
$- 2 {x}^{2} - 9x + 5 = 0$
obrigada​

Answer 1

Resposta:

-2x²-9x+5=0

a=-2 b=-9 c=5

Δ=b²-4ac

Δ=(-9)²-4×(-2)×5

Δ=81+40

Δ=121

x= -b±√Δ ÷ 2a

x= -(-9)±√121 ÷2×(-2)

x= 9±11÷-4

x₁ = 9+11÷-4

x₁=20÷-4

x₁= - 5

x₂= 9-11÷ -4

x₂= -2÷-4

x₂= 1÷2

S= {-5 ; 1÷2}

Answer 2

Resposta: S = {-5, 1/2}

Explicação passo-a-passo:

-2x² - 9x + 5 = 0

Δ = b² - 4*a*c

Δ = (-9)² - 4*(-2)*5

Δ = 81 + 40

Δ = 121

√Δ = 11

x' = - b ± √Δ/2*a

x' = 9 + 11/2*(-2)

x' = 20/-4

x' = - 5

-----------------------------

x" = - b - √Δ/2*a

x" = 9 - 11/2*(-2)

x" = -2/-4

x" = 1/2

S = { -5, 1/2}

bons estudos