Question

Calcule usando a fórmula de Bhaskara x^2-8x+12=0

Answer 1

fórmula de Bhaskara x=-b±√∆/2a
x²-8x+12=0
a=1
b=-8
c=12
∆=b²-4ac
∆=(-8)²-4*1*12
∆=64-48
∆=16

X=-(-8)±√16/2
x=8±4/2
x1=8-4/2
x1=2

x2=8+4/2
x2=6

S={2,6}

Answer 2

x²-8x+12=0

a= 1, b= -8, c= 12

delta= b²-4.a.c

delta= (-8)²-4.1.12
delta= 64-48
delta= 16

x= -b±√delta/2.a

x= 8±√16/2.1

x= 8±4/2

x= 8+4/2= 12/2= 6

x= 8-4/2= 4/2= 2

s={ 6,2 }