Question

Calcule:$\sqrt{ 2^{3}+ 1^{2} }$

Answer 1

x = $\sqrt{2^3+1^2}$
x = $\sqrt{8+1}$
x = $\sqrt{9}$
x = $3$

Answer 2

$\sqrt{2^{3}+1^{2}} = \sqrt{8+1} = \sqrt{9} = 3 \\ 2^{3} = 2*2*2 = 4*2 = 8 \\ 1^{2} = 1*1 = 1 \\ \\ Resposta: 3$