Question

Calcule  [tex] \frac{ i^{91}+ 2i^{52}- 3i^{48} }{ 3i^{1002}- 5i^{400} }

Answer 1

$\frac{ i^{91}+ 2i^{52}- 3i^{48} }{ 3i^{1002}- 5i^{400}} \\ \\ \frac{-1+2-3}{3i-5}=\frac{-2}{3i-5} \\ \\ \boxed{\frac{-2}{3i-5}.\frac{3i+5}{3i+5}=\frac{-(6i+5)}{-34}=\frac{6i+5}{34}}$

Answer 2

Resposta:

Explicação passo-a-passo:

-i + 2 . 1 - 3 . 1 / 3 . -1 - 5 . 1

-i + 2 - 3 / -3 - 5

-i - 1 /-8

=> 1 + i/8