Question

calcule:
$(\frac{7a}{5} - 2ab + { \frac{b}{3} }^{2} ) + (4ab - { \frac{b}{3} }^{2} )$
e
$( { \frac{x}{3} }^{2} + \frac{2x}{5} - \frac{1}{4}) + ( { \frac{2x}{3} }^{2} - \frac{1}{4})$

Answer 1

$( \frac{7a}{5} - 2ab + \frac{ {b}^{2} }{3} ) + (4ab - \frac{ {b}^{2} }{3} ) \\ elimine \: \frac{ + {b}^{2} }{3} com \: \frac{ - {b}^{2} }{3} \\ \frac{7a}{5} - 2ab + 4ab \\ \frac{7a}{5} + 2ab$